Using the LT1073 step-up 4 AA batteries to 12V, to get simple instructions? I hung a PIR to IC 555, so I'm timer and motion detector works, but the output is fairly week. I have an IC LT1073 and want to take the output pin 3 of IC 555 (around 3V +) 12V.
I need simple instructions for what happens to this pine how, R1 connects? from? pin, R2 goes? pin? Point.
I will use the LED light, I already know how to calculate the resistance of the LED # x # of lines, etc. ..
I am totally lost and would appreciate a step-by-step similar to page 3 @ http://www.kpsec.freeuk.com/docs/breadbrd.pdf.
Thank you
If you can not read a schematic with parts 5-10 on it, you're in over your head, and the need to learn the basics before going into more complex circuits. But using a 1073 is not a good approach.
The output voltage of the A555 is not a power that can be speeded up or down. He did not much current capacity. As the response of other words, using the 555 from 12 volts, or use a switch transistor.
Also note that the 555 can run much more power in the low state (up to 250 mA) that can be obtained at the high state. Thus, the 555 can drive a large number of LEDs in the low state. In the high state, a single buffer transistor will allow him to drive at least 200 mA the value of the LED.
Email me if you need more info.
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http://www.datasheetcatalog.org/datashee ... Go to page 12, there are a few examples of step converters.
Want to reduce the level of the 555 too? Why not run the 555 from 12V? Or you could put out the 555 in a small transistor, and use it as a switch to connect to your LED 12v produced by the circuit STEPUP.
Posted on August 10, 2010.
